Question

Find the sum of money that amounts to rupees 8250 in 5years at the interest rate of 7.5 per annum

Answer 1

Answer:

The sum of money (principal) = 6000 rupees

Step-by-step explanation:

Given:

Amount = 8250 rupees

Time = 5 years (Y)

Rate of interest = 7.5 % per annum (R)

To find:

Principal amount (P)

Amount = Principal + Simple interest

$simple \: interest = \frac{p \times r \times t}{100}$

Substituting the values,

$simple \: interest = \frac{p \times 7.5 \times 5}{100}$

Simple interest = 0.375×p

Amount = 8250

So Substituting the values of principal and simple interest, we get:

p + 0.375×p = 8250

1.375 p = 8250

Principal = 6000 rupees

Simple interest = 2250 rupees

The sum of money is equal to 6000 rupees

Answer 2

$\large\red{\underline{\underline{\bf{\blue{Given}}}}}$

• Amount (A) = 8250

• Time (T) = 5 years

• Rate (R) = 7.5 % per annum

$\large\red{\underline{\underline{\bf{\blue{To Find}}}}}$

• Principal (P)

$\large\red{\underline{\underline{\bf{\blue{Solution}}}}}$

We know that,

$Simple \: Interest \: (SI) = \frac{PRT}{100}$

So, put all the above given values in it

We get,

$SI \: = \frac{p \times 7.5 \times 5}{100} = \frac{3P}{8} = 0.375P$

Now,

We also know that,

Amount (A) = Principal (P) + Interest (I)

So,

8250 = P + 0.375P

8250 = 1.375P

P = 8250/1.375 = 6000

Hence,

Principal (P) = 6000

MORE FORMULAS :-

$Simple \: Interest \: = \frac{PRT}{100} \\ \\ Amount = Principal + Interest \\ \\ Time = \frac{i \times 100}{PR} \\ \\ Rate = \frac{i \times 100}{PT} \\ \\ Principal = \frac{i \times 100}{RT}$