Find the sum of money when the final amount is Rs11300 at 4% p.a. for 3 years 3 months.
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sum of money = p
rate = 4 %
time = 3 years 3 months
amount = 11300
changing 3 years 3 months to years
3 years + 3 / 12 years
3 years + 1 / 4 years
(12 + 1) / 4 years
13 / 4 years
so, time = 13 / 4 years
![simple \: interest \: = \frac{p \times r \times t}{100} \\ \frac{p \times 4 \times \frac{13}{4}}{100} \\ \frac{p \times 13}{100} \\ simple \: interest \: = \frac{p \times r \times t}{100} \\ \frac{p \times 4 \times \frac{13}{4}}{100} \\ \frac{p \times 13}{100} \\](https://tex.z-dn.net/?f=simple+%5C%3A+interest+%5C%3A+%3D+%5Cfrac%7Bp+%5Ctimes+r+%5Ctimes+t%7D%7B100%7D+%5C%5C+%5Cfrac%7Bp+%5Ctimes+4+%5Ctimes+%5Cfrac%7B13%7D%7B4%7D%7D%7B100%7D+%5C%5C+%5Cfrac%7Bp+%5Ctimes+13%7D%7B100%7D+%5C%5C+)
amount = simple interest + principal
S.i + p = 13p/100
S.i = 13/100
amount - simple interest = principle
11300 - 13 / 100
(1130000 - 13) / 100
1129987 / 100
11299.87
sum of money = 1129 9.87
Mark It As Brainliest Answer.
rate = 4 %
time = 3 years 3 months
amount = 11300
changing 3 years 3 months to years
3 years + 3 / 12 years
3 years + 1 / 4 years
(12 + 1) / 4 years
13 / 4 years
so, time = 13 / 4 years
amount = simple interest + principal
S.i + p = 13p/100
S.i = 13/100
amount - simple interest = principle
11300 - 13 / 100
(1130000 - 13) / 100
1129987 / 100
11299.87
sum of money = 1129 9.87
Mark It As Brainliest Answer.
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