Math, asked by akhilasounderrajan, 9 months ago

find the sum of money which becomes rupees 14,520 in 2 years at a compound interest rate of 10°per annum

Answers

Answered by hmishra156
13

Answer:

Rs.12000

Step-by-step explanation:

Easy formula for C.I.

A for C.I(compound interest) = P{ 1 +(r/100)}^t   (just a formula dude;)

where a is amount = Rs.14520

where p is principal = ?(we have to find!)

r is rate of interest = 10% P.a.

t is time = 2 years

Understanding the question

The question is not asking for the final, instead it is asking for the initial principal.

Solving the question

A = P{ 1 +(r/100)}^t

A/[{ 1 +(r/100)}^t] = P (we have to find the amount!)

14520/[{ 1+(10/100)}^2] = P (just putting the value)

14520/(1.1)^2 = P

14520/1.21 = P

P = 12000 (Easy! try to understand)

Conclusion

∴ the initial sum of money was Rs.12,000.

Answered by anjusrivastav2028
3

Answer:

A=P/[{1+(r/100)}^t]

14520/[{1+/100)}^2]=P

14520/(1.1)^2=P

P=14520/1.21

P=12000

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