find the sum of multiples of 3 upto 1000
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here a is 3 or 5 or 15, and n is 999 or
1000 but 999 is best, and then sum
multiples of 3:
3((333) (333+1)/2)=166833 plus
multiples of 5:
5(199)-(199+1)/2)=99500; and
subtract multiples of 15 15((66)+
(66+1)/2)=33165 to get 233168.
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