Question

find the sum of multiplicative inverse and additive inverse of 9​

Answer 1

$Given \: number = 9$

$Multiplicative \: inverse \: 9 \:is \: \frac{1}{9}$

$Additive \: inverse \:of \:9 \:is \: (-9)$

/* According to the problem given */

the sum of multiplicative inverse and additive inverse of 9

$Sum = \frac{1}{9} + (-9) \\= \frac{1}{9} - 9 \\= \frac{1-81}{9}\\= \frac{-80}{9}$

Therefore.,

$\red {Sum }\green {=\frac{-80}{9} }$

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