Math, asked by indrakumar84, 1 year ago

find the sum of n arithmetic means between x and 3x.​

Answers

Answered by Anonymous
8

Step-by-step explanation:

If there are n means, then [x,3x] is divided into n+1 intervals.

Thus, you have an arithmetic sequence where

a = x

d = (3x-x)/(n+1) = 2x/(n+1)

x, x + 2x/(n+1), x + 4x/(n+1), ... x + 2nx/(n+1), x + 2(n+1)x/(n+1)

= x, (n+3)/(n+1) x, (n+5)/(n+1) x, ... 3(n+1)/(n+1) x

Answered by NightUmbrella
6

If there are n means, then [x,3x] is divided into n+1 intervals.

If there are n means, then [x,3x] is divided into n+1 intervals.Thus, you have an arithmetic sequence where

If there are n means, then [x,3x] is divided into n+1 intervals.Thus, you have an arithmetic sequence wherea = x

If there are n means, then [x,3x] is divided into n+1 intervals.Thus, you have an arithmetic sequence wherea = xd = (3x-x)/(n+1) = 2x/(n+1)

If there are n means, then [x,3x] is divided into n+1 intervals.Thus, you have an arithmetic sequence wherea = xd = (3x-x)/(n+1) = 2x/(n+1)x, x + 2x/(n+1), x + 4x/(n+1), ... x + 2nx/(n+1), x + 2(n+1)x/(n+1)

If there are n means, then [x,3x] is divided into n+1 intervals.Thus, you have an arithmetic sequence wherea = xd = (3x-x)/(n+1) = 2x/(n+1)x, x + 2x/(n+1), x + 4x/(n+1), ... x + 2nx/(n+1), x + 2(n+1)x/(n+1)= x, (n+3)/(n+1) x, (n+5)/(n+1) x, ... 3(n+1)/(n+1) x

hope this will help you dear !!!

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