find the sum of n natural numbers
NikhitaDreamer:
The answer is [n (n+1)] /2
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Answered by
5
The formula is {n (n+1)} /2
where n is the no of natural numbers
where n is the no of natural numbers
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Answered by
5
the first natural number (a)= 1
and common difference (d) = 1
Sn=n/2×{2a+(n-1)d}
Sn=n/2×(2+n-1) --------[since a=1 and d=1]
Sn= n(n+1)/2
and common difference (d) = 1
Sn=n/2×{2a+(n-1)d}
Sn=n/2×(2+n-1) --------[since a=1 and d=1]
Sn= n(n+1)/2
thankx
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