Question

Find the sum of 'N' term of the sequence 4,10,16 ?

Answer 1

The sequence is an arithmetic progression with first term a = 4

and common difference, d = 10-4 = 6

So, Sum of N terms = N/2*(2a + (N-1)d) =N/2*(2*4 + (N-1)6)

= N/2 * (8 + 6N - 6) = N/2 * (6N + 2) = 3N² + N