Find the sum of n terms in the given series
1^2+2^2+........+n^2
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[(n)(n+1)(2n+1)]/6 is the formula
mvbbtg44:
Can I get to know how to solve it pls
u can use the identity k^3 - (k-1)^3 = 3k^2 - 3k +1
to prove the following
it is very easy u can do by urself
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