Question

find the sum of n terms of an AP is given by an=2n square+3n then the common difference of A.P is​

Answer 1

Answer:

S1 = 3(1) + 2(1)2 = 5 = t1

S2 = 3(2) + 2(2)2 = 14 = t1 + t2

∴ S2 - S1 = 9 = t2

∴ d = t2 - t1 = 9 - 5 = 4

Step-by-step explanation:

S1 = 3(1) + 2(1)2 = 5 = t1

S2 = 3(2) + 2(2)2 = 14 = t1 + t2

∴ S2 - S1 = 9 = t2

∴ d = t2 - t1 = 9 - 5 = 4