Find the sum of n terms of sequence 6,66,666,nterms
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Answer:
Step-by-step explanation:
6 , 66 , 666 ,
6 , 6×10 + 6 , 6×100 + 6×10 + 6
6×10^0 . 6×10^1 + 6×10^0 , 6×10^2 + 6×10^1+ 6×10^0
Adding all upto n terms
=n×6×10^0 + (n-1)×6×10^1 + (n-2)×6×10^2 + ..................+(n-(n-2))×6×10^(n-2) + (n-(n-1))×6×10^(n-1)
=n×6×10^0 + (n-1)×6×10^1 + (n-2)×6×10^2 + ..................+2×6×10^(n-2) + 1×6×10^(n-1)
= 6 ×( n×10^0 + (n-1)10^1 + (n-2)10^2 + ..................+2×10^(n-2) + 1×10^(n-1) )
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