Math, asked by ksatishkumaryadav139, 1 year ago

Find the sum of n terms of sequence 6,66,666,nterms

Answers

Answered by amitnrw
5

Answer:


Step-by-step explanation:

6  , 66   , 666 ,    

6  , 6×10  + 6  , 6×100 + 6×10 + 6  

6×10^0  . 6×10^1 + 6×10^0  , 6×10^2 + 6×10^1+ 6×10^0

Adding all upto n terms

=n×6×10^0 + (n-1)×6×10^1 + (n-2)×6×10^2 + ..................+(n-(n-2))×6×10^(n-2) +               (n-(n-1))×6×10^(n-1)

=n×6×10^0 + (n-1)×6×10^1 + (n-2)×6×10^2 + ..................+2×6×10^(n-2) +               1×6×10^(n-1)

= 6 ×( n×10^0 + (n-1)10^1 + (n-2)10^2 + ..................+2×10^(n-2) +               1×10^(n-1) )

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