Question

find the sum of n terms of series (4-1/n) + (4-2/n) + (4-3/n) +.....

Answer 1

I just came to bed so I cannot show he written answer. but I can tell the approach.
the sequence is 3/n+2/n+1/n+0+....
it is an A.P.
first term, a= 3/n
common difference, d= -1/n
Number of terms= N
formula = N/2 x 2a+(N-1)d