Question

Find the sum of n terms of series whose Tnth term is given n cube - 3n square +2n​

Answer 1

Answer:

Given : T = n^3 - 3n^2 + 2n

On doing summation :

£->Summation

Then : £T = £n^3 - £3n^2 + £2n

£T = (n(n+1)/2)^2 - 3n(n+1)(n+2)/6 + 2n(n+1)/2

= (n(n+1)/2)^2 - n(n+1)(n+2)/2 + n(n+1)

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