Question

Find the sum of n terms of the AP √6, √24, √54, √96.........

Answer 1

Answer:

sum = √6(3 + n)/2

Step-by-step explanation:

here, a=√6

d=√24 - √6 = √6(√4 - 1) = √6(2-1) = √6

sum = 1/2[2a + (n + 1)d] = 1/2[2√6 + (n + 1)√6] = 1/2[2√6 + n√6 + √6]

       = 1/2(3√6 + n√6) = √6(3 + n)/2