Question

Find the sum of n terms of the AP n+(n +2) +(n + 4) +(n +6).​

Answer 1

Answer:

n=n terms

d=2

a^n=n+6

a=n

S^n=n/2(2a+(n-1)d)

=n/2(2×n+(n-1)2)

=n/2(2n+2n-2)

=n/2×2(n+n-1)

=n(2n-1)

=2n*2-n

I guess this is the answer.