Find the sum of n terms of the series 2 + 4 + 6 +8+...+2n.
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Answer:
sum of n terms (Sn)=n/2 (x1+xn)
where, x1=first term
xn=nth term
Sn=n/2(2+2n)
n/2×2+ n/2×2n
2n/2 + 2n^2 /2
n+n^2
Sn= n+n^2
Answered by
4
Answer:
i hope it helps u................
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