Find the Sum of natural from 20 to 80?
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(20,21.........80)
a=20
difference =1
an =80
nth term = an = a+ (n-1)d
80=20+(n-1)1
80=20+(n-1)
60 =n-1
61=n
sum of natural numbers which is from 20 to 80 is
sn=n/2(2a +(n-1)d)
sn=61/2(2(20)+(60)1)
sn=61/2(40+60)
sn =61/2(100)
sn=6100/2
sn=3050
PlZ MARK ME AS A BRAINLIST
a=20
difference =1
an =80
nth term = an = a+ (n-1)d
80=20+(n-1)1
80=20+(n-1)
60 =n-1
61=n
sum of natural numbers which is from 20 to 80 is
sn=n/2(2a +(n-1)d)
sn=61/2(2(20)+(60)1)
sn=61/2(40+60)
sn =61/2(100)
sn=6100/2
sn=3050
PlZ MARK ME AS A BRAINLIST
kattananibabu19:
I marked u as a brilliant for ur explanation
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