Question

find the sum of natural no.s which differ by 3 nd ehose squared have the sum 149

Answer 1

10 and 7 as 10 * 10=100 and & 7*7=49 
therefore the numbers are 10 and 7. hope you like it please mark brainliest and click thanks

Answer 2

Let the no.s be x and y.......; (1) x=3+y 
(2) x*x + y*y=149
Substituting (1) in (2), we get
 (3+y)2 + y*y=149
9+y*y+6y+y*y=149
2y2+6y+9=149........(By quadratic equation)
(y+3)(y+3)=149
y= 146
x=146+3=149
sum of the natural no.s= 146+149=295