Question

find the sum of natural number divisible by 5 between 2 and 101​

Answer 1

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Answer 2

Answer: Sum of natural number divisible by 5 between 2 and 101 is 1050.

Step-by-step explanation:

Since we have given that

Numbers divisible by 5 between 2 and 101.

So, that numbers are

5,10,15,......................100

Here, a = 5

d = $a_2-a_1=10-5=5$

Now, we will find the number of terms 'n'.

$a_n=a+(n-1)d\\\\100=5+(n-1)5\\\\100-5=5(n-1)\\\\95=5(n-1)\\\\\frac{95}{5}=n-1\\\\19=n-1\\\\19+1=n\\\\20=n$

Now, we will find the sum of natural numbers divisible by 5.

So, our equation becomes,

$S_{20}=\frac{20}{2}(2a+(n-1)d)\\\\S_{20}=10(2\times 5+(20-1)\times 5)\\\\S_{20}=10(10+19\times 5)\\\\S_{20}=10(10+95)\\\\S_{20}=105\times 10\\\\S_{20}=1050$

Hence, Sum of natural number divisible by 5 between 2 and 101 is 1050.