Question

find the sum of natural numbers between 1 to 150 ​

Answer 1

Answer:

first term (a)=1

last term (t n)=150

difference(d)=1

sum(sn)=?

now

tn = a+ (n-1)*d

150=1+(n-1)*1

149=n-1

n=150

so

sn= n/2[2*a+(n-1)*d]

= 150/2[2*1+(150-1)*1]

= 75*(2+149)

= 75*151

= 11325

Please mark me as brainliest

Answer 2

very easy natural number of 1 to 100 be

1,2,3,4,5,6,7,8,9,10,....................,150