find the sum of natural numbers between 20 and 100
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Hey there!
num of terms=80
1st term=20
common difference=1
Sn= n/2(2a+(n-1)d)
Sn= 80/2(40+79 . 1)
Sn= 80/2(119)
Sn= 40(119) = 4760
Hope it help
num of terms=80
1st term=20
common difference=1
Sn= n/2(2a+(n-1)d)
Sn= 80/2(40+79 . 1)
Sn= 80/2(119)
Sn= 40(119) = 4760
Hope it help
goyalvikas78:
pls mark as brainliest
how u got common difference 1
a1 = 20 and a2 = 21 so common difference = a2 - a1 => 21-20 =>1
> is >
sorry & gt; is actually the arrow sign
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