Question

find the sum of natural numbers from 1 to 30 and algebraic expression of an arithmetic sequence is 4n+ 3 then find the sum of first 30 terms
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Answer 1

Answer:

Step-by-step explanation:

Sum Of First 30 Natural numbers,

S = n/2(a+l)

S = 30/5(1+30)

S = 6(31) = 186.

Arithmetic Sequence = 4n+3.

1st Term = 4(1)+3 = 7.

2nd Term = 4(2)+3 = 11.

3rd Term = 4(3)+3 = 15.

Therefore, a = 7 , d = 4.

Sum Of First 30 Terms = n = 30

S = n/2(2a+(n-1)d)

S = 15(2(7)+(30-1)4)

S = 15(14+116)

S = 15*130

S = 1950.

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