Question

find the sum of natural numbers from 100 to 300 which is divisible by 6. give the methos wise ans pls give fast​

Answer 1

Step-by-step explanation:

So the natural numbers between 100 to 300 and also divisible by 6 are

102,108,114,.........,300

Now let the number 300 is n'th term in this ap series

Here difference(d) =6

First term (a) =102

Therefore..

N'th term=1st term+(n-1)d

300=102+(n-1)6

300-102=6n-6

(198+6)/6=n

n=204/6

n=34

Now...

S(34)=(34/2)(102+300)

=17*402

=6834