Question

find the sum of natural numbers lie between 100 to 150 which are divisable by a using formula​

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

It contains the concept of arithmetic progression.

100,104,108……..300 are divisible by 4. So the common difference is 4 and the last term is 300.

Using the formula a+(n-1)d, we knew that 300 is the 51st term (=n) of A.P.

Now we use the formula of sum of n terms of A.P. i.e. n/2(first term + last term) and putting the values 51/2(100+300)

we get 10200 as the answer.

So simple:-)