find the sum of nature numbers from 100 to 400
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Answer:
1,65,550
Step-by-step explanation:
The natural numbers from 100 to 400 forms an AP with first term 100 and common difference 1.
The number of terms in sequence 100,101,102,...,399,400 is 400-99=301.
So sum of AP is given by,
Sn = n/2(2a + (n-1)d)
Sn = 301/2(2(400) + (301-1)(1))
Sn = 301/2(800 + 300)
Sn = 301/2(1100)
Sn = 301*550
Sn = 1,65,550
This is your answer.
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