Question

find the sum of no. from 98 to 400 which are divisible by 4 giving reminder 2​

Answer 1

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The numbers lying between 200 and 400 which are divisible by 7 are 203,210,217,...399

∴ First term,  a=203

Last term, an=399 & Common difference, d=7

Let the number of terms of the A.P. be n.

∴an=399=a+(n−1)d⇒399=203+(n−1)7⇒7(n−1)=196⇒n−1=28⇒n=29∴S29=229(203+399)=229(602)=(29)(301)=8729

Thus, the required sum is 8729

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Answer 2

Answer:

$\huge{\mathcal {\purple {A}\green {n}\pink {s}\blue {w}\purple{e}\green {r}}}$

The numbers lying between 200 and 400 which are divisible by 7 are 203,210,217,...399

∴ First term,  a=203

Last term, an=399 & Common difference, d=7

Let the number of terms of the A.P. be n.

∴an=399=a+(n−1)d⇒399=203+(n−1)7⇒7(n−1)=196⇒n−1=28⇒n=29∴S29=229(203+399)=229(602)=(29)(301)=8729

Thus, the required sum is 8729

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