find the sum of number divisible by 6 from 1 to 100
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Originally Answered: What is the sum of the numbers between 1 and 100 which are divisible by 6? => n = (96–6)/6 + 1=15+1=16. = 8[12 + 90] = 8*102= 816.
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Mathematics 9
16 Numbers are divisible by 6 which lies 1 to 100. Hnce, The Sum Of 16 Term which lies 1 to 100 and also divisible by 6 is 816.
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