Question

find the sum of numbers between 1 and 100 divisible by 6

Answer 1

Sn=51n. is the if value of n is given the u can use. it

Answer 2

NUMBERS Which is divisible by 6 are 6,12,18,....96.

AP = 6,12,18,.....96

Here,

A = 6

D = 6

Tn = 96

a+(n-1) × d = 96

6+(n-1) × 6 = 96

6+6n-6 = 96

6n = 96

n = 96/6 = 16

Hence,

16 Numbers are divisible by 6 which lies 1 to 100.

So,

N = 16

Sn = N/2[ 2a+(n-1)×d]

S16 = 16/2[2×6 + (16-1) × 6]

= 8(12+15×6)

= 8( 12+90)

= 8×102 = 816

Hence,

The Sum Of 16 Term which lies 1 to 100 and also divisible by 6 is 816.



I HOPE IT WILL HELP YOU..

THANKS