Find the sum of numbers between 1 to 100 divisible by 6
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16 numbers are divisible by 6 between 1 to 100
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AP=6,12,18.........,96
96=6+(n-1)6
96-6=6n-6
90+6=6n
96/6=n
n=16
Sn=16/2(2*6+(16-1)6)
=8(12+90)
=8*102
=816
Hope it is helpful
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