find the sum of numbers between 5 and 250 that are multiples of 4
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First term in this series will be 12. also the last digit will be 248.
the the series will be 12,16,20……….248.
it is a arithmetic series with first term a=12 and common difference of 4.
with last term as 248.
so 248=12+(n-1)x4 (lets assume it has n such numbers.)
(n-1).4= 248–12=236
n-1=236/4=59
n=59+1=60.
so 60 multiples of 4 lie between 10 and 250.
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