find the sum of numbers from 50 to 120 which are divisible by 7
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the numbers are 56,63,70,77,84,91,98,105,112,119.
sum=875
n=10
first number=56
last number=119
sum=1/2×n(first number+last number)
=5×(119+56)=175×5=875
sum=875
n=10
first number=56
last number=119
sum=1/2×n(first number+last number)
=5×(119+56)=175×5=875
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