find the sum of numbers which lying between 250 and ,400 whose hcf is 36
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1. The nos. should have 36 in their factorisation , so let them be 36n , 36m and so on.
2. The nos. lie between 250 and 400 so n, m and other variables must be between 7 and 11
3. From 7 , 8 , 9 , 10 , 11 we have to choose nos. with no common factor, so the pairs are => (7,8,9,11) and (7,9,10,11)
36 * 7 = 252
36 * 8 = 288
36 * 9 = 324
36 * 10 = 360
36 * 11 = 396
Rest you can make pairs and find the sum.
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