Question

find the sum of odd integers from 1 to 2001​

Answer 1

$\huge{\underline{\purple{\mathbb{♡ANSWER♡}}}}$

a=1, d=2

1+(n-1)2=2001

2n-2=2001

n=1001

Sn=1001/2(2×1+(1001-1)×2)

=1001/2(2+1000×2)

=1001/2×2002

=1001×1001

$\huge \boxed{1002001}$

hope it helps you☜

Answer 2

Answer:

this is the solution

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