Question

find the sum of odd integers from 1 to 999

Answer 1

Step-by-step explanation:

Sum of all integers from 1–999 is 1000 x 999/2=499500. Subtract the sum of all the even numbers. This is obviously the equivalent of double the sum of all the integers from 1–499,which is 2 x 500 x 499/2= 249500. Same result as the other answers,250000,but I think it's a simpler method to calculate it

Hope it helps:-):-):-)

Answer 2

Step-by-step explanation:

for odd integer

a = first term = 1

d is common difference is 2

Sn=n/2[2a+(n-1)d]

Tn=a+(n-1)d

999=1+(n-1)2

998/2=n-1

499+1=n

500=n

by putting n =500 in Sn

we get

S500=250[2+499×2]

=250[2+998]

=250×1000

=250000

thank you

plz mark as brainliest