Question

Find the sum of odd intiger fron 1 to 100

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

$S_n=\dfrac{a_1+a_n}{2}\cdot n\\a_1=1\\a_n=99\\d=2\\\\a_n=a_1+(n-1)\cdot d\\99=1+(n-1)\cdot 2\\2n-2=98\\2n=100\\n=50\\\\S_{50}=\dfrac{1+99}{2}\cdot 50=50\cdot 50=2500$

or this way

$1+3+5+\ldots+99=1+99+3+97+\ldots+49+51=25\cdot 100=2500$