Find the sum of odd natural number from 1 to 200
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Answer:
10,000
Step-by-step explanation:
a1 = 1
d = 2
an = 199 = a + (n-1)d
199 = 1 + (n-1)2
199 = 1 + 2n - 2
199 = -1 + 2n
200 = 2n
n = 100.
Sum = S100 = 100/2 ( 2(1) + (100-1) 2)
[ Sn = n/2 ( 2a + (n-1)d ) ]
S100 = 50 ( 2 + 2(99) )
= 50 ( 2 + 198 )
= 50 x 200 = 10,000
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