Find the
Sum of
of interior angle: n=5
h=6
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We know that sum of interior angles of a polygon of side n is (n-2) x 180 so let tn =(n-2) x 180
∵tnislinearinn,soitisn
th
termofsomeAP
t3=180,n=3
t4=2×180,n=4
t5=3×180,n=5
t4−t3=180,
t5−t4=180
commondiffernceis180
Sum of interior angles of polygon with 3, 4, 5, .sides forms an AP.
Now sum of interior angles of 21 sides polygon is
t21=(21−2)×180
19×180
3420
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PLEASE.
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