Question

find the sum of oll first ,n, odd numbers​

Answer 1

Answer:

bro we dont no what the 'n' number is

so :we dont have end to odd numders

we can't sum n odd numbers okkk any dout ask me

Answer 2

Answer:

2n+(n*n)

Step-by-step explanation:

Sum of n terms of an AP =

n/2[2a+(n-1)d]

where ,a is the first term

d. is the common difference

sum of first n odd no. =

here, first term is 3 and common difference is 2.

n/2[2*3+(n-1)2] =

n/2[6+2n-2] =

n/2[4+2n] =

4n+2n^2/2 =

2n+n^2

or

2n+(n*n)