Find the sum of opposite angles of an isoscleles trapizium
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Hello dear user!!✌️✌️
Here is your answer goes like this :
=============================================
DC and the alternate interior angles are supplementary.
So, the angles ∠A and ∠D are supplementary
which means
∠A + ∠D = 180
Similarly, ∠B and ∠C are supplementary.
so, ∠B + ∠C = 180
Since the trapezium is the isosceles trapezium, the base angles are equal.
∠C = ∠D
So by subsituting the anles we get
∠A + ∠C = 180
∠B + ∠D = 180
============================================
I HOPE THIS WILL HELP YOU ✌️✌️
HAVE A GREAT DAY DEAR...... :)
^_^
Here is your answer goes like this :
=============================================
DC and the alternate interior angles are supplementary.
So, the angles ∠A and ∠D are supplementary
which means
∠A + ∠D = 180
Similarly, ∠B and ∠C are supplementary.
so, ∠B + ∠C = 180
Since the trapezium is the isosceles trapezium, the base angles are equal.
∠C = ∠D
So by subsituting the anles we get
∠A + ∠C = 180
∠B + ∠D = 180
============================================
I HOPE THIS WILL HELP YOU ✌️✌️
HAVE A GREAT DAY DEAR...... :)
^_^
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