find the sum of p square ,-q square ,q square,-r square,r square,-p square
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Answer:there can be two answers of this question as you have not mentioned the condition. So , if p²-q²+q²-r²+r²-p² then its is equal to 0.
But if p²+(-q²)+q²+(-r²)+r²+(-p²) then it is equal to 2(p²+q²+r²).
Step-by-step explanation:
So, taking first condition.
If p²-q²+q²-r²+r²-p² then
p² and -p² will cancel each other and
q² and -q² will cancel each other and
r² and -r² will cancel each other.
Hence, the answer will be equal to zero(0).
Now, taking 2nd condition i.e., if
p²+(-q²)+q²+(-r²)+r²+(-p²) then
=p²+q²+q²+r²+r²+p²
=2p²+2q²+2r²
=2(p²+q²+r²)
Hence, the answer will be 2(p²+q²+r²).
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