Question

Find the sum of prime numbers from 1 to 100 which when divided by 2 leaves the remainder as 1 and when divided by 3 leaves the remainder as 2.​

Answer 1

Answer:

The least common multiple of 2, 3, 4, 5, 6 is their LCM=60.

So, the answer is the least number such that it is a multiple of 7 and a multiple of 60 leaving remainder 1.

∴The required answer is 301