Question

Find the sum of prime numbers from 1 to 100 which when divided by 4 and 5 leaves the remainder 1 and 4 respectively.

Answer 1

Primes that divided by 4 then remainder is 1
= 5,13,17,19,37,41,53,61,89,97

Primes that divided by 5 then remainder is 4
=19,29,59,79,89

Sum=5+13+17+19+29+37+41+53+59+61+79+89+97
=666

Answer 2

prime numbers
=2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97.


divisible by 4 then remainder 1 5,13,17,19,37,41,53,61,89,97


divisible by 5 then remainder 4
=19,29,59,79,89


sum of prime number
=5+13+17+19+37+41+53+61+89+97+19+29+59+79+89=666.


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