find the sum of product and the polynomial 3x2+6x-2
Answers
Answer:
we have to find sum and product of zeroes of the given polynomial 3x² + 6x-2
Since we know the general form of quadratic polynomial = ax² + bx + c
sum of zeroes = - coefficient of x/coefficient of x² = -b/a
sum of zeroes = - coefficient of x/coefficient of x² = -b/a product of zeroes = constant/coefficient of x² = c/a
on comparing 3x² + 6x - 2 with ax² + bx + c we get, a = 3, b = 6 and c = - 2
So, the sum of zeroes = -b/a = -(6)/3 = 2
product of zeroes = c/a = (2)/3 = 2/3 or .67
hence, sum of zeroes = 2
and product of zeroes = 2/3
Answer:
we have to find sum and product of zeroes of the given polynomial 3x² + 6x-2
Since we know the general form of quadratic polynomial = ax² + bx + c
sum of zeroes = - coefficient of x/coefficient of x² = -b/a
sum of zeroes = - coefficient of x/coefficient of x² = -b/a product of zeroes = constant/coefficient of x² = c/a
on comparing 3x² + 6x - 2 with ax² + bx + c we get, a = 3, b = 6 and c = - 2
So, the sum of zeroes = -b/a = -(6)/3 = 2
product of zeroes = c/a = (2)/3 = 2/3 or .67
hence, sum of zeroes = 2
and product of zeroes = 2/3
Step-by-step explanation: