find the sum of real roots of the equation x^2+|x| -6=0.
Answers
Answered by
79
Answer:
0
Step-by-step explanation:
suppose x is positive x^2 +x - 6= 0
[x+3] [x-2] =0
x = -3 or x= 2 x is positive so x=2
suppose x is negative x^2 -x - 6= 0
[x-3] [x+2] =0
x = 3 or x= -2 x is negative so x=-2
now x=2 and -2 are roots
sum =0
another method
IxI = k is roots then x= k and x= -k are roots
so sum =0
Answered by
0
Answer:
Real roots are x= -3,2
Step-by-step explanation:
To find the real root
x =-b ±√b²-4ac/2a
= -(1)±√1²-4(1)(-6)/2(1)
= -1±√1+24/2
=-1±√25/2
= -1±5/2
x= -1+5/2 (or) -1-5/2
= 4/2 (or) -6/2
= 2 (or) -3
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