Question

find the sum of roots of equation 3x^2-9x+5=0​

Answer 1

$\huge\underline{\bf \orange{Solution :}}$

• Let's the roots of the given equation be α and β

Now , According to formula

$\large \implies \boxed{ \tt \alpha + \beta = \dfrac{ - b}{a} }$

Here

• a = 3
• b = - 9
• c = 5

Substitute values in formula :-

$\implies \tt \alpha + \beta = \frac{ - ( - 9)}{3} \\ \\ \implies \tt \alpha + \beta = \frac{ 9}{3} \\ \\ \implies \boxed{ \tt \alpha + \beta =3}$

Sum of roots of the equation is 3

Answer 2

${\huge{\bf{\pink{\mathfrak{\underline{\underline{Solution}}}}}}}$

Solution:

Let's the roots of the given equation be α and β

Now , According to formula

\large \implies \boxed{ \tt \alpha + \beta = \dfrac{ - b}{a} }⟹

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀α+β= -b /a

⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀

Here,

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀a = 3

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀b = - 9

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀c = 5

Substitute values in formula :-

\begin{gathered}\implies \tt \alpha + \beta = \frac{ - ( - 9)}{3} \\ \\ \implies \tt \alpha + \beta = \frac{ 9}{3} \\ \\ \implies \boxed{ \tt \alpha + \beta =3}\end{gathered}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⟹α+β= -(-9)/3

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⟹α+β= 9/3

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⟹ α+β=3

Sum of roots of the equation is 3.