Question

find the sum of series 1,6,11,16...up to 30 terms.​

Answer 1

Answer:

S30 = 2205

Step-by-step explanation:

Sn = n/2 [2a + (n -1)d]

S30 = 30/2 [2×1 + (30-1)5]

= 15 [2 + 29×5]

= 15 [2 + 145]

= 15 (147)

= 2205

Answer 2

Answer:

2205

Step-by-step explanation:

a=1, d=5

Formula:-

Sⁿ$=\frac{n}{2}[2(a)+(n-1)d]$

S₃₀=$\frac{30}{2}[2(1)+(30-1)5]$

    =15[2+29(5)]

    =15(147)

    =2205

Therefore sum of 30 terms is 2205

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