Question

Find the sum of series (2^3-1)+(4^3-3^3)+(6^3-5^3)+.....to n terms and 8terms

Answer 1

Answer:

(2³-1)+(4³-3³)+(6³-5³)+(8³-7³)+(10³-9³)+(12³-11³)+(14³-13³)+(16³-15³)

=(8-1)+(64-27)+(216-125)+(512-343)+(1000-729)+(1728-1331)+(2744-2197)+(4096-3375)

=7+37+91+169+271+397+547+721

=ANSWER: 2240

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