Question

find the sum of series-3,+3,+9,+15......... uptown 16 terms​

Answer 1

Step-by-step explanation:

the given ap : -3,3,9,15...

a = -3

d = 3-(-3) = 6

n= 16

the formula to find the sum of n terms of ap = n/2(2a + (n-1)d)

putting the values, we get = 16/2(2×-3 +(16-1)6)

= 8(-6 + 15×6) = 8(-6 +90) = 8×84 = 672

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Answer 2

Answer:

This series is an AP

here ,

first term, a = -3

common difference ,d = 3 -(-3)

= 6

sum of n terms =(n/2) (2a +(n -1)d)

sum of 16 terms =(16 /2 )[2 (-3) +(16-1)6]

=8 [-6 + (15×6)]

= 8 [-6 + 90 ]

= 8 [84 ]

=672