Find the sum of series
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Hello dear!
Here is your answer,
We know that 2 to 100, there are 50 even numbers.
So, from 2 to 200, there are 100 even numbers.
So, n = 100
Now, we also know that the sum of even numbers starting from 2 to 'n' terms is given by n ( n + 1 ).
Substitute the values we get,
n ( n + 1 )
=> 100 ( 100 + 1 )
=> 100 × 101
=> 10100
Answer : 10100
Here is your answer,
We know that 2 to 100, there are 50 even numbers.
So, from 2 to 200, there are 100 even numbers.
So, n = 100
Now, we also know that the sum of even numbers starting from 2 to 'n' terms is given by n ( n + 1 ).
Substitute the values we get,
n ( n + 1 )
=> 100 ( 100 + 1 )
=> 100 × 101
=> 10100
Answer : 10100
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