find the sum of sixteen terms of an AP -1,-5,-9
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s16=n/2 (2a+(n-1)d)
s16=8(2(-1)+(15)-4)
s16=8(-62)
s16=-496
i guess it will help
s16=8(2(-1)+(15)-4)
s16=8(-62)
s16=-496
i guess it will help
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16-1 we want mines Bro answer is wrong
sorry bro
How¿
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corrected
its ok
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